The magnitude of gravitational field at distance r₁ and r₂ from the centre of a uniform sphere of radius R and mass M are E₁ and E₂ respectively. If r₁ > R and r₂ < R, then the ratio E₁/E₂ is (a) (R²)/(r₁ r₂) (b) (R³)/(r₁ r₂²) (c) (R³)/(r₁² r₂) (d) (R⁴)/(r₁² r₂²)

Answer: (c). Outside ( r₁ > R): E₁ = (GM)/(r₁²). Inside ( r₂ < R): E₂ = (GMr₂)/(R³). (E₁)/(E₂) = (R³)/(r₁² r₂) So the answer is (c) (R³)/(r₁² r₂).

The magnitude of gravitational field at distance r₁ and r₂ from the… | MHT CET 2026 (13 May, Shift 2)

Q2MHT CET 2026 · 13 MAY · SHIFT 2Medium

Gravitational Field

The magnitude of gravitational field at distance $r_1$ and $r_2$ from the centre of a uniform sphere of radius $R$ and mass $M$ are $E_1$ and $E_2$ respectively. If $r_1 > R$ and $r_2 < R$ , then the ratio $E_1/E_2$ is

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Answer: (c)

Outside ( $r_1 > R$ ): $E_1 = \frac{GM}{r_1^2}$ .
Inside ( $r_2 < R$ ): $E_2 = \frac{GMr_2}{R^3}$ .
$\frac{E_1}{E_2} = \frac{R^3}{r_1^2 r_2}$
So the answer is (c) $\frac{R^3}{r_1^2 r_2}$ .

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Gravitational Field question from MHT CET 2026 (13 May, Shift 2)

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