The magnitude of gravitational field at distances r₁ and r₂ from the centre of a uniform sphere of radius R and mass M are I₁ and I₂ respectively. Given that r₁ > R and r₂ < R, the ratio (I₁)/(I₂) is (a) (R²)/(r₁ r₂) (b) (R³)/(r₁ r₂²) (c) (R³)/(r₁² r₂) (d) (R⁴)/(r₁² r₂²)

Answer: (c). Outside ( r₁ > R): I₁ = (GM)/(r₁²). Inside ( r₂ < R): I₂ = (GMr₂)/(R³). (I₁)/(I₂) = (GM)/(r₁²)·(R³)/(GMr₂) = (R³)/(r₁² r₂) So the answer is (c) (R³)/(r₁² r₂).

The magnitude of gravitational field at distances r₁ and r₂ from the… | MHT CET 2026 (14 May, Shift 2)

Q1MHT CET 2026 · 14 MAY · SHIFT 2Medium

Gravitational Field

The magnitude of gravitational field at distances $r_1$ and $r_2$ from the centre of a uniform sphere of radius R and mass M are $I_1$ and $I_2$ respectively. Given that $r_1 >$ $R$ and $r_2 <$ $R$ , the ratio $\frac{I_1}{I_2}$ is

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Answer: (c)

Outside ( $r_1 > R$ ): $I_1 = \frac{GM}{r_1^2}$ .
Inside ( $r_2 < R$ ): $I_2 = \frac{GMr_2}{R^3}$ .
$\frac{I_1}{I_2} = \frac{GM}{r_1^2}\cdot\frac{R^3}{GMr_2} = \frac{R^3}{r_1^2 r_2}$
So the answer is (c) $\frac{R^3}{r_1^2 r_2}$ .

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Gravitational Field question from MHT CET 2026 (14 May, Shift 2)

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