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MHT CET 2025 (22 Apr, Shift 2) · Gravitational Potential & Energy

Gravitational Potential & Energy question from MHT CET 2025 (22 Apr, Shift 2)

Q6MHT CET 2025 · 22 APR · SHIFT 2Medium

Gravitational Potential & Energy

The magnitude of gravitational potential energy of a body at a distance ' RR ' from the centre of the earth is ' E '. Its weight at a distance ' 1.5 R ' from the centre of the earth is

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Answer: (c)

  1. E=GMmR⇒GMm=ERE = \frac{GMm}{R} \Rightarrow GMm = ER
  2. Weight at r=1.5Rr = 1.5R: W=GMm(1.5R)2=ER2.25R2W = \frac{GMm}{(1.5R)^2} = \frac{ER}{2.25R^2}
  3. So the answer is (c) W=4E9RW = \frac{4E}{9R}.
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