The magnitude of magnetic field at point 'O' in the following figure will be (a) (μ₀)/(4π)I/r(2/π + 2) (b) (μ₀)/(4π)I/r(2/π - 2) (c) (μ₀)/(4π)I/r(2 + π/2) (d) (μ₀)/(4π)I/r(2 - π/2)

Answer: (c). AB and CD are semi-infinite, ending at the feet of the perpendiculars from O: each gives (μ₀)/(4π)I/r. Quarter arc BC: (μ₀ I)/(8r) = (μ₀)/(4π)I/r · π/2 All are out of the page: B = (μ₀)/(4π)I/r(2 + π/2) So the answer is (c).

The magnitude of magnetic field at point 'O' in the following figure… | MHT CET 2024 (10 May, Shift 2)

Q33MHT CET 2024 · 10 MAY · SHIFT 2Medium

Magnetic Field of Straight Wires

The magnitude of magnetic field at point 'O' in the following figure will be

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Answer: (c)

AB and CD are semi-infinite, ending at the feet of the perpendiculars from O: each gives $\frac{\mu_0}{4\pi}\frac{I}{r}$ .
Quarter arc BC: $\frac{\mu_0 I}{8r} = \frac{\mu_0}{4\pi}\frac{I}{r} \cdot \frac{\pi}{2}$
All are out of the page: $B = \frac{\mu_0}{4\pi}\frac{I}{r}\left(2 + \frac{\pi}{2}\right)$
So the answer is (c).

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