The magnitude of magnetic induction at mid point 'O' due to current arrangement as shown in figure will be ( μ₀ = permeability of free space) (a) (μ₀ I)/(2π a) (b) zero (c) (μ₀ I)/(4π a) (d) (μ₀ I)/(π a)

Answer: (d). O lies on the line of AB and DE, so these horizontal parts give zero. BC and ET are semi-infinite, each starting level with O at distance a/2: each gives (μ₀ I)/(4π (a/2)) = (μ₀ I)/(2π a). Both point out of the page, so B = (μ₀ I)/(π a) So the answer is (d).

The magnitude of magnetic induction at mid point 'O' due to current… | MHT CET 2026 (16 Apr, Shift 2)

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Magnetic Field of Straight Wires

The magnitude of magnetic induction at mid point 'O' due to current arrangement as shown in figure will be ( $\mu_0$ = permeability of free space)

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Answer: (d)

O lies on the line of AB and DE, so these horizontal parts give zero.
BC and ET are semi-infinite, each starting level with O at distance $\frac{a}{2}$ : each gives $\frac{\mu_0 I}{4\pi (a/2)} = \frac{\mu_0 I}{2\pi a}$ .
Both point out of the page, so $B = \frac{\mu_0 I}{\pi a}$
So the answer is (d).

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