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JEE Main 2026 (28 Jan, Shift 1) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2026 (28 Jan, Shift 1)

Q9JEE Main 2026 · 28 JAN · SHIFT 1Medium

Spherical Surfaces & Thin Lenses

The magnitudes of power of a biconvex lens (refractive index 1.5) and that of a plano-concave lens (refractive index =1.7= 1.7) are same. If the curvature of planoconcave lens exactly matches with the curvature of back surface of the biconvex lens, then ratio of radius of curvature of front and back surface of the biconvex lens is ______

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Answer: (b)

  1. Biconvex (front R1R_1, back R2R_2): P1=0.5(1R1+1R2)P_1 = 0.5\left(\frac{1}{R_1} + \frac{1}{R_2}\right).
  2. Plano-concave with radius R2R_2: ∣P2∣=0.7R2|P_2| = \frac{0.7}{R_2}.
  3. 0.5R1+0.5R2=0.7R2⇒0.5R1=0.2R2\frac{0.5}{R_1} + \frac{0.5}{R_2} = \frac{0.7}{R_2} \Rightarrow \frac{0.5}{R_1} = \frac{0.2}{R_2}
  4. R1R2=0.50.2=52\frac{R_1}{R_2} = \frac{0.5}{0.2} = \frac{5}{2}
  5. So the answer is (b) 5:25 : 2.
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