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JEE Main 2019 (11 Jan, Shift 2) · Simple Pendulum

Simple Pendulum question from JEE Main 2019 (11 Jan, Shift 2)

Q71JEE Main 2019 · 11 JAN · SHIFT 2Easy

Simple Pendulum

The mass and the diameter of a planet are three times the respective values for the Earth. The period of oscillation of simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:

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Answer: (d)

Diameter $3\times$ means radius $3\times$ : $g' = \frac{G(3M)}{(3R)^2} = \frac{g}{3}$ .
$T \propto \frac{1}{\sqrt{g}} \Rightarrow T' = 2\sqrt{3}\text{ s}$
So the answer is (d) $2\sqrt{3}$ s.

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