The mass defect in a particular reaction is 0.4 g. The amount of energy liberated is n × 10⁷ kWh, where n = __________. (speed of light = 3 × 10⁸ m/s) Numerical answer type. Work it out, then open the answer.

Answer: 1. E = Δ m c² = 0.4 × 10⁻³ × 9 × 10¹⁶ = 3.6 × 10¹³ J 1 kWh = 3.6 × 10⁶ J, so E = 3.6 × 10¹³3.6 × 10⁶ = 1 × 10⁷ kWh So n = 1

The mass defect in a particular reaction is 0.4 g. The amount of… | JEE Main 2024 (31 Jan, Shift 1)

Q8JEE Main 2024 · 31 JAN · SHIFT 1Easy

Mass Defect & Binding Energy

The mass defect in a particular reaction is $0.4\text{ g}$ . The amount of energy liberated is $n \times 10^{7}\text{ kWh}$ , where $n =$ __________. (speed of light $= 3 \times 10^{8}\text{ m/s})$

Numerical answer type. Work it out, then open the answer.

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Answer: 1

$E = \Delta m\, c^2 = 0.4 \times 10^{-3} \times 9 \times 10^{16} = 3.6 \times 10^{13}$ J
$1\ \text{kWh} = 3.6 \times 10^6$ J, so $E = \dfrac{3.6 \times 10^{13}}{3.6 \times 10^6} = 1 \times 10^7$ kWh
So $n = 1$

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Mass Defect & Binding Energy question from JEE Main 2024 (31 Jan, Shift 1)

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