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MHT CET 2021 (22 Sep, Shift 1) · Escape Velocity

Escape Velocity question from MHT CET 2021 (22 Sep, Shift 1)

Q44MHT CET 2021 · 22 SEP · SHIFT 1Easy

Escape Velocity

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. If the escape velocity from the earth is ' $V_e$ ', then the escape velocity from the planet is

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Answer: (a)

$v_e = \sqrt{\frac{2GM}{R}} \propto \sqrt{\frac{M}{R}}$
$\frac{v_p}{V_e} = \sqrt{\frac{6}{2}} = \sqrt{3}$
So the answer is (a) $\sqrt{3}V_e$ .

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