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JEE Main 2023 (1 Feb, Shift 1) · Mass Defect & Binding Energy

Mass Defect & Binding Energy question from JEE Main 2023 (1 Feb, Shift 1)

Q12JEE Main 2023 · 1 FEB · SHIFT 1Easy

Mass Defect & Binding Energy

The mass of proton, neutron and helium nucleus are respectively 1.0073 u,1.0087 u1.0073\,u, 1.0087\,u and 4.0015 u4.0015\,u. The binding energy of helium nucleus is:

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Answer: (a)

  1. Δm=2(1.0073)+2(1.0087)−4.0015=4.0320−4.0015=0.0305\Delta m = 2(1.0073) + 2(1.0087) - 4.0015 = 4.0320 - 4.0015 = 0.0305 u
  2. BE=0.0305×931≈28.4BE = 0.0305 \times 931 \approx 28.4 MeV
  3. So the answer is (a) 28.4 MeV.
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