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JEE Main 2021 (26 Feb, Shift 1) · Progressive Wave Equation

Progressive Wave Equation question from JEE Main 2021 (26 Feb, Shift 1)

Q78JEE Main 2021 · 26 FEB · SHIFT 1Medium

Progressive Wave Equation

The mass per unit length of a uniform wire is 0.135 g/cm. A transverse wave of the form y = −- 0.21 sin (x + 30t) is produced in it, where x is in meter and t is in second. Then, the expected value of tension in the wire is x ×\times 10−-2 N. Value of x is _________. (Round off to the nearest integer)

Numerical answer type. Work it out, then open the answer.

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Answer: 1215

  1. μ=0.135 g/cm=0.0135 kg/m\mu = 0.135\text{ g/cm} = 0.0135\text{ kg/m}
  2. v=ωk=301=30 m/sv = \frac{\omega}{k} = \frac{30}{1} = 30\text{ m/s}
  3. T=μv2=0.0135×900=12.15 N=1215×10−2 NT = \mu v^2 = 0.0135 \times 900 = 12.15\text{ N} = 1215 \times 10^{-2}\text{ N}
  4. So x=1215x = 1215.
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