Physics Circle home Student Login

Home›Chapters›Mechanical Properties of Solids PYQs›Young's Modulus & Elongation›Question 8

NEET 2024 · Young's Modulus & Elongation

Young's Modulus & Elongation question from NEET 2024

Q8NEET 2024Medium

Young's Modulus & Elongation

The maximum elongation of a steel wire of 1 m1\text{ m} length if the elastic limit of steel and its Young's modulus, respectively, are 8×108 N m−28 \times 10^{8}\text{ N m}^{-2} and 2×1011 N m−22 \times 10^{11}\text{ N m}^{-2}, is:

Show answer and solution

Answer: (a)

  1. Maximum stress is the elastic limit, so maximum strain =8×1082×1011=4×10−3= \frac{8 \times 10^{8}}{2 \times 10^{11}} = 4 \times 10^{-3}
  2. Δlmax=strain×L=4×10−3×1=4×10−3 m\Delta l_{max} = \text{strain} \times L = 4 \times 10^{-3} \times 1 = 4 \times 10^{-3}\text{ m}
  3. So the answer is (a) 4 mm.
Report a mistake

More questions on Young's Modulus & Elongation