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JEE Main 2024 (5 Apr, Shift 2) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2024 (5 Apr, Shift 2)

Q10JEE Main 2024 · 5 APR · SHIFT 2Easy

Time of Flight, Maximum Height & Range

The maximum height reached by a projectile is 64 m64\text{ m}. If the initial velocity is halved, the new maximum height of the projectile is ______ m\text{m}.

Numerical answer type. Work it out, then open the answer.

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Answer: 16

  1. H∝u2H \propto u^2 for the same angle.
  2. Halving uu: H′=H4=644H' = \frac{H}{4} = \frac{64}{4}
  3. New maximum height =16 m= 16\text{ m}.
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