The maximum kinetic energy of the emitted photoelectrons in photoelectric effect is independent of: (a) work function of material (b) intensity of incident radiation (c) frequency of incident radiation (d) wavelength of incident radiation

Answer: (b). Kmax = hν - φ = (hc)/(λ) - φ. It depends on φ, ν and λ, but intensity does not appear. So the answer is (b) intensity of incident radiation.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The maximum kinetic energy of the emitted photoelectrons in photoelectric effect is independent of:

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Answer: (b)

$K_{max} = h\nu - \phi = \dfrac{hc}{\lambda} - \phi$ .
It depends on $\phi$ , $\nu$ and $\lambda$ , but intensity does not appear.
So the answer is (b) intensity of incident radiation.

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