Student Login

Home›Chapters›Oscillations PYQs›Energy in SHM›Question 6

MHT CET 2026 (16 Apr, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2026 (16 Apr, Shift 2)

Q6MHT CET 2026 · 16 APR · SHIFT 2Easy

Energy in SHM

The maximum potential energy of a block executing S.H.M. is E and amplitude of oscillation is 'A'. The kinetic energy of the block at amplitude A/2 is

Show answer and solution

Answer: (a)

Maximum PE = total energy $E = \dfrac{1}{2}kA^2$ .
At $x = A/2$ : $PE = \dfrac{1}{2}k\dfrac{A^2}{4} = \dfrac{E}{4}$
$KE = E - \dfrac{E}{4} = \dfrac{3E}{4}$
So the answer is (a) $\dfrac{3E}{4}$ .

Report a mistake

More questions on Energy in SHM

For a particle P performing S.H.M., when displacement is 'x', potential energy and…MHT CET 2026 (16 Apr, Shift 1)
The amplitude of a particle executing SHM is 3 cm. The displacement at which its kinetic…MHT CET 2026 (13 Apr, Shift 2)
For a simple pendulum, having time period T, the variation of kinetic energy (K.E.) with…NEET 2026
A linear harmonic oscillator of force constant 2 × 10⁶ N/m has amplitude 0.01 m. ItsMHT CET 2026 (19 May, Shift 2)
A mass 0.4 kg performs S.H.M. with a frequency 16/π Hz. At a certain displacement it has…MHT CET 2026 (11 Apr, Shift 2)
Maximum kinetic energy of a particle of mass 1 kg in S.H.M. is 8 J and the time period is…MHT CET 2026 (14 May, Shift 1)
A particle of mass ' m ' is executing S.H.M. about the origin on x-axis with frequency…MHT CET 2026 (18 Apr, Shift 2)
A block is fastened to a horizontal spring. The block is pulled to a distance x = 10 cm…MHT CET 2026 (13 Apr, Shift 2)