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MHT CET 2023 (9 May, Shift 1) · Velocity & Acceleration in SHM

Velocity & Acceleration in SHM question from MHT CET 2023 (9 May, Shift 1)

Q41MHT CET 2023 · 9 MAY · SHIFT 1Easy

Velocity & Acceleration in SHM

The maximum velocity of a particle performing S.H.M. is 'VV'. If the periodic time is made (13)\left(\frac{1}{3}\right)rd and the amplitude is doubled, then the new maximum velocity of the particle will be

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Answer: (d)

  1. vmax=2πATv_{max} = \frac{2\pi A}{T}, so vmax∝ATv_{max} \propto \frac{A}{T}
  2. A′=2AA' = 2A, T′=T3T' = \frac{T}{3}: v′=2×3 V=6Vv' = 2\times 3\,V = 6V
  3. So the answer is (d) 6V6V.
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