The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are 3 × 10⁻⁷ m and 600 m/s, respectively. Find the frequency of its collisions. (a) 5 × 10⁸/s (b) 9 × 10⁵/s (c) 2 × 10¹⁰/s (d) 2 × 10⁹/s

Answer: (d). Collision frequency f = ( v)/(λ) f = 6003×10⁻⁷ = 2×10⁹ s⁻¹ So the answer is (d) 2×10⁹ /s.

The mean free path and the average speed of oxygen molecules at 300 K… | JEE Main 2025 (4 Apr, Shift 1)

Q4JEE Main 2025 · 4 APR · SHIFT 1Easy

Mean Free Path & Real Gases

The mean free path and the average speed of oxygen molecules at 300 K and 1 atm are $3 \times 10^{-7}\text{ m}$ and $600\text{ m/s}$ , respectively. Find the frequency of its collisions.

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Answer: (d)

Collision frequency $f = \dfrac{\bar v}{\lambda}$
$f = \dfrac{600}{3\times10^{-7}} = 2\times10^{9}\text{ s}^{-1}$
So the answer is (d) $2\times10^9$ /s.

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