Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Satellites - Orbital Velocity & Period›Question 79

NEET 1992 (AIPMT) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from NEET 1992 (AIPMT)

Q79NEET 1992 · AIPMTEasy

Satellites - Orbital Velocity & Period

The mean radius of earth is RR, its angular speed on its own axis is ω\omega and the acceleration due to gravity at earth's surface is gg. What will be the radius of the orbit of a geostationary satellite?

Show answer and solution

Answer: (a)

  1. Geostationary satellite has angular speed ω\omega: GMr2=ω2r\frac{GM}{r^2} = \omega^2 r.
  2. r3=GMω2=gR2ω2r^3 = \frac{GM}{\omega^2} = \frac{gR^2}{\omega^2} (using GM=gR2GM = gR^2).
  3. So the answer is (a) (R2g/ω2)1/3(R^2g/\omega^2)^{1/3}.
Report a mistake

More questions on Satellites - Orbital Velocity & Period