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JEE Main 2022 (29 Jul, Shift 2) · Simple Pendulum

Simple Pendulum question from JEE Main 2022 (29 Jul, Shift 2)

Q58JEE Main 2022 · 29 JUL · SHIFT 2Medium

Simple Pendulum

The metallic bob of simple pendulum has the relative density 5. The time period of this pendulum is 10 s10\text{ s}. If the metallic bob is immersed in water, then the new time period becomes 5x5\sqrt{x} s. The value of xx will be ________.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. Relative density 5: geff=g(1−15)=4g5g_{eff} = g\left(1 - \frac{1}{5}\right) = \frac{4g}{5}.
  2. T′=Tggeff=1054=55 sT' = T\sqrt{\frac{g}{g_{eff}}} = 10\sqrt{\frac{5}{4}} = 5\sqrt{5}\text{ s}.
  3. So x=5x = 5.
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