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MHT CET 2022 (11 Aug, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2022 (11 Aug, Shift 2)

Q65MHT CET 2022 · 11 AUG · SHIFT 2Medium

Spherical Surfaces & Thin Lenses

The minimum distance between an object and its real image formed by a convex lens of focal length 'f' is

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Answer: (b)

Object–image distance $D = |u| + v$ for a real image.
With $\frac{1}{v} + \frac{1}{|u|} = \frac{1}{f}$ , $D$ is minimum when $|u| = v = 2f$ .
$D_{min} = 2f + 2f = 4f$
So the answer is (b) $4f$ .

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