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JEE Main 2024 (1 Feb, Shift 1) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2024 (1 Feb, Shift 1)

Q22JEE Main 2024 · 1 FEB · SHIFT 1Medium

Transitions, Photon Emission & Excitation

The minimum energy required by a hydrogen atom in ground state to emit radiation in Balmer series is nearly:

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Answer: (c)

  1. Balmer lines end on n=2n = 2, so the atom must first reach at least n=3n = 3.
  2. Minimum energy =13.6(1−19)=12.09= 13.6\left(1 - \frac{1}{9}\right) = 12.09 eV
  3. So the answer is (c) ≈12.1\approx 12.1 eV.
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