The molar specific heats of an ideal gas at constant pressure and volume are denoted by ' Cp ' and ' Cv ' respectively. If γ = (Cp)/(Cv) and ' R ' is universal gas constant, then Cv is equal to (a) (R)/(γ-1) (b) γ R (c) (1+γ)/(1-γ) (d) (γ-1)/(R)

Answer: (a). Cp - Cv = R and Cp = γ Cv. Cv(γ-1) = R ⇒ Cv = (R)/(γ-1) So the answer is (a) (R)/(γ-1).

The molar specific heats of an ideal gas at constant pressure and… | MHT CET 2021 (21 Sep, Shift 1)

Q38MHT CET 2021 · 21 SEP · SHIFT 1Easy

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

The molar specific heats of an ideal gas at constant pressure and volume are denoted by ' $C_p$ ' and ' $C_v$ ' respectively. If $\gamma = \frac{C_p}{C_v}$ and ' $R$ ' is universal gas constant, then $C_v$ is equal to

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Answer: (a)

$C_p - C_v = R$ and $C_p = \gamma C_v$ .
$C_v(\gamma-1) = R \Rightarrow C_v = \frac{R}{\gamma-1}$
So the answer is (a) $\frac{R}{\gamma-1}$ .

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2021 (21 Sep, Shift 1)

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