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MHT CET 2021 (23 Sep, Shift 2) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2021 (23 Sep, Shift 2)

Q33MHT CET 2021 · 23 SEP · SHIFT 2Easy

Rotational Kinetic Energy, Work & Power

The moment of inertia of a body about the given axis, rotating with angular velocity 1 rad/s is numerically equal to 'P' times its rotational kinetic energy. The value of 'P' is

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Answer: (c)

$K = \frac{1}{2}I\omega^2$ ; with $\omega = 1$ rad/s, $K = \frac{I}{2}$
$I = 2K \Rightarrow P = 2$
So the answer is (c) 2.

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