The moment of inertia of a circular disc of radius 2 m and mass 1 kg about an axis XY passing through its centre of mass and perpendicular to the plane of the disc is 2 kg m². The moment of inertia about an axis parallel to the axis XY and passing through the edge of the disc is (a) 6 kg m² (b) 4 kg m² (c) 10 kg m² (d) 8 kg m²

Answer: (a). Parallel axis theorem with d = R = 2 m: I = Icm + MR². I = 2 + 1 × 2² = 6 kg m² So the answer is (a) 6 kg m².

The moment of inertia of a circular disc of radius 2 m and mass 1 kg… | MHT CET 2021 (21 Sep, Shift 1)

Q132MHT CET 2021 · 21 SEP · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

The moment of inertia of a circular disc of radius $2\text{ m}$ and mass $1\text{ kg}$ about an axis XY passing through its centre of mass and perpendicular to the plane of the disc is $2\text{ kg m}^2$ . The moment of inertia about an axis parallel to the axis $XY$ and passing through the edge of the disc is

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Answer: (a)

Parallel axis theorem with $d = R = 2\text{ m}$ : $I = I_{cm} + MR^2$ .
$I = 2 + 1 \times 2^2 = 6\text{ kg m}^2$
So the answer is (a) $6\text{ kg m}^2$ .

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