The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1/xMR², where R is the radius and M is the mass of the semicircular ring. The value of x will be __________. Numerical answer type. Work it out, then open the answer.

Answer: 1. All mass of the semicircular ring is at distance R from the centre. I = Σ m R² = MR² So x = 1.

The moment of inertia of a semicircular ring about an axis, passing… | JEE Main 2023 (8 Apr, Shift 1)

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Moment of Inertia & Radius of Gyration

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is $\frac{1}{x}MR^2$ , where $R$ is the radius and $M$ is the mass of the semicircular ring. The value of $x$ will be __________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 1

All mass of the semicircular ring is at distance $R$ from the centre.
$I = \sum m R^2 = MR^2$
So $x = 1$ .

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