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JEE Main 2025 (28 Jan, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from JEE Main 2025 (28 Jan, Shift 1)

Q48JEE Main 2025 · 28 JAN · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in similar way. The moment of inertia of a solid sphere which has same radius as the disc and rotating in similar way, is nn times higher than the moment of inertia of the given ring. Here, n=n = ________ Consider all the bodies have equal masses.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

  1. Equal masses, so radii differ. Disc about diameter 14MRd2\frac{1}{4}MR_d^2, ring about diameter 12MRr2\frac{1}{2}MR_r^2.
  2. 14Rd2=2.5×12Rr2⇒Rd2=5Rr2\frac{1}{4}R_d^2 = 2.5 \times \frac{1}{2}R_r^2 \Rightarrow R_d^2 = 5R_r^2
  3. Sphere (radius RdR_d): Is=25MRd2=2MRr2I_s = \frac{2}{5}MR_d^2 = 2MR_r^2.
  4. n=2MRr212MRr2=4n = \frac{2MR_r^2}{\frac{1}{2}MR_r^2} = 4
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