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NEET 2011 (AIPMT, Prelims) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from NEET 2011 (AIPMT, Prelims)

Q183NEET 2011 · AIPMT · PRELIMSEasy

Moment of Inertia & Radius of Gyration

The moment of inertia of a thin uniform rod of mass M and length L about an axis passing through its midpoint and perpendicular to its length is $I$ 0. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is

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Answer: (b)

Parallel axis theorem: $I = I_{cm} + Md^2$ .
The end is at $d = L/2$ from the midpoint, so $I = I_0 + M(L/2)^2$ .
So the answer is (b) $I_0 + ML^2/4$ .

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