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NEET 2005 (AIPMT) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from NEET 2005 (AIPMT)

Q192NEET 2005 · AIPMTEasy

Moment of Inertia & Radius of Gyration

The moment of inertia of a uniform circular disc of radius R and mass M about an axis passing from the edge of the disc and normal to the disc is

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Answer: (c)

$I_{cm} = \frac{1}{2}MR^2$ about the central normal axis.
Shift to the edge ( $d = R$ ): $I = \frac{1}{2}MR^2 + MR^2$ .
So the answer is (c) $\frac{3}{2}MR^2$ .

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