Moment of Inertia & Radius of Gyration question from NEET 2012 (AIPMT, Mains)

Answer: (a)

1. $I = \frac{MR^2}{2} + Md^2$ increases with the distance $d$ of the axis from the centre.
2. $B$ lies on the rim ($d = R$); $A$ is the centre and $C$, $D$ are inside.
3. $I_B = \frac{3}{2}MR^2$ is the maximum.
4. So the answer is (a) B.