The moment of inertia of two rotating bodies 'X' and 'Y' are I₁ and I₂ respectively where I₂ > I₁. If Kx and Ky are their rotational kinetic energies and their angular momenta are equal, then (a) Kx = Ky (b) Kx > Ky (c) Kx < Ky (d) Kx = Ky/2

Answer: (b). K = L²/2I; for equal L, K ∝ 1/I I₁ Ky So the answer is (b) Kx > Ky.

The moment of inertia of two rotating bodies 'X' and 'Y' are I₁ and… | MHT CET 2026 (20 May, Shift 1)

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Rotational Kinetic Energy, Work & Power

The moment of inertia of two rotating bodies 'X' and 'Y' are $I_1$ and $I_2$ respectively where $I_2 > I_1$ . If $K_x$ and $K_y$ are their rotational kinetic energies and their angular momenta are equal, then

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Answer: (b)

$K = \frac{L^2}{2I}$ ; for equal $L$ , $K \propto \frac{1}{I}$
$I_1 < I_2 \Rightarrow K_x > K_y$
So the answer is (b) $K_x > K_y$ .

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