The momentum of a photon of energy 1 MeV in kg m/s will be (a) 5 × 10 - 22 (b) 0.33 × 106 (c) 7 × 10 - 24 (d) 10 - 22

Answer: (a). E = 1 MeV = 1.6 × 10⁻¹³ J p = E/c = 1.6 × 10⁻¹³3 × 10⁸ = 5.3 × 10⁻²² kg m/s So the answer is (a) 5 × 10⁻²².

The momentum of a photon of energy 1 MeV in kg m/s will be | NEET 2006 (AIPMT)

Q38NEET 2006 · AIPMTEasy

Photons: Energy, Momentum & Radiation Pressure

The momentum of a photon of energy 1 MeV in kg m/s will be

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Answer: (a)

$E = 1\text{ MeV} = 1.6 \times 10^{-13}\text{ J}$
$p = \frac{E}{c} = \frac{1.6 \times 10^{-13}}{3 \times 10^{8}} = 5.3 \times 10^{-22}\text{ kg m/s}$
So the answer is (a) $5 \times 10^{-22}$ .