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NEET 2012 (AIPMT, Prelims) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from NEET 2012 (AIPMT, Prelims)

Q36NEET 2012 · AIPMT · PRELIMSEasy

Velocity, Acceleration & Variable Motion

The motion of a particle along a straight line is described by equation x = 8 + 12t $-$ t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is

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Answer: (d)

$v = \frac{dx}{dt} = 12 - 3t^2 = 0 \Rightarrow t = 2$ s.
$a = \frac{dv}{dt} = -6t = -12$ m/s $^2$ at $t = 2$ s.
So the retardation is (d) 12 m s $^{-2}$ .

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