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MHT CET 2024 (15 May, Shift 2) · Periodic Motion & SHM Basics

Periodic Motion & SHM Basics question from MHT CET 2024 (15 May, Shift 2)

Q25MHT CET 2024 · 15 MAY · SHIFT 2Easy

Periodic Motion & SHM Basics

The motion of a particle is described by the equation $a = -bx$ where ' $a$ ' is the acceleration, x is the displacement from the equilibrium position and b is a constant. The periodic time will be

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Answer: (b)

Compare $a = -bx$ with $a = -\omega^2 x$ : $\omega = \sqrt{b}$ .
$T = \frac{2\pi}{\omega} = \frac{2\pi}{\sqrt{b}}$ .
So the answer is (b) $\frac{2\pi}{\sqrt{b}}$ .

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