The motion of a simple pendulum executing S.H.M. is represented by the following equation. y = Asin (π t + φ), where time is measured in second. The length of pendulum is (a) 97.23 cm (b) 25.3 cm (c) 99.4 cm (d) 406.1 cm

Answer: (c). Comparing with y = Asin (ω t + φ): ω = π rad/s, so T = 2 s. ω² = g/l ⇒ l = (g)/(ω²) = (9.8)/(π²) l ≈ 0.994 m = 99.4 cm So the answer is (c) 99.4 cm.

The motion of a simple pendulum executing S.H.M. is represented by… | JEE Main 2022 (29 Jun, Shift 2)

Q51JEE Main 2022 · 29 JUN · SHIFT 2Easy

Simple Pendulum

The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A\sin(\pi t + \phi)$ , where time is measured in second. The length of pendulum is

Show answer and solution

Answer: (c)

Comparing with $y = A\sin(\omega t + \phi)$ : $\omega = \pi$ rad/s, so $T = 2$ s.
$\omega^2 = \frac{g}{l} \Rightarrow l = \frac{g}{\omega^2} = \frac{9.8}{\pi^2}$
$l \approx 0.994$ m $= 99.4$ cm
So the answer is (c) 99.4 cm.

Report a mistake

Simple Pendulum question from JEE Main 2022 (29 Jun, Shift 2)

More questions on Simple Pendulum