Graphs of Motion question from JEE Main 2025 (23 Jan, Shift 1)

Answer: (a)

1. Distance = area under the $v$-$t$ graph.
2. 0 to 2 s (trapezium): $\frac{1}{2}(200 + 400)\times 2 = 600\text{ m}$
3. 2 s to 30.5 s (rectangle): $400\times 28.5 = 11400\text{ m}$
4. Total $= 12000\text{ m} = 12\text{ km}$. So the answer is (a).