The net impedance of circuit (as shown in figure) will be: (a) 15 Ω (b) 5√(5) Ω (c) 25 Ω (d) 10√(2) Ω

Answer: (b). XL = 2π f L = 2π × 50 × 50/π × 10⁻³ = 5 Ω XC = 12π × 50 × (10³)/(π) × 10⁻⁶ = 10 Ω Z = √(10² + (10 - 5)²) = √(125) = 5√(5) Ω So the answer is (b) 5√(5) Ω.

The net impedance of circuit (as shown in figure) will be: | NEET 2023

Q36NEET 2023Easy

Series LCR Circuit

The net impedance of circuit (as shown in figure) will be:

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Answer: (b)

$X_L = 2\pi f L = 2\pi \times 50 \times \frac{50}{\pi} \times 10^{-3} = 5\ \Omega$
$X_C = \frac{1}{2\pi \times 50 \times \frac{10^3}{\pi} \times 10^{-6}} = 10\ \Omega$
$Z = \sqrt{10^2 + (10 - 5)^2} = \sqrt{125} = 5\sqrt{5}\ \Omega$
So the answer is (b) $5\sqrt{5}\ \Omega$ .

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