The nuclei ₆C¹³ and ₇N¹⁴ can be described as (a) isotones (b) isobars (c) isotopes of carbon (d) isotopes of nitrogen

Answer: (a). Neutrons in ₆C¹³: 13 - 6 = 7. Neutrons in ₇N¹⁴: 14 - 7 = 7. Same N, different Z and A, so they are isotones. So the answer is (a) isotones.

The nuclei ₆C¹³ and ₇N¹⁴ can be described as | NEET 1990 (AIPMT)

Q45NEET 1990 · AIPMTEasy

Nucleus: Composition, Size & Nuclear Force

The nuclei ${}_{6}\text{C}^{13}$ and ${}_{7}\text{N}^{14}$ can be described as

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Answer: (a)

Neutrons in ${}_{6}\text{C}^{13}$ : $13 - 6 = 7$ .
Neutrons in ${}_{7}\text{N}^{14}$ : $14 - 7 = 7$ .
Same $N$ , different $Z$ and $A$ , so they are isotones.
So the answer is (a) isotones.

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