The nucleus ₆C¹² absorbs an energetic neutron and emits a beta particle ( β). The resulting nucleus is (a) ₇N¹⁴ (b) ₇N¹³ (c) ₅B¹³ (d) ₆C¹³

Answer: (b). Neutron absorption: ₆C¹² + ₀n¹ → ₆C¹³ β⁻ emission: A unchanged, Z up by 1: ₆C¹³ → ₇N¹³ + e⁻ So the answer is (b) ₇N¹³.

The nucleus ₆C¹² absorbs an energetic neutron and emits a beta… | NEET 1990 (AIPMT)

Q47NEET 1990 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

The nucleus ${}_{6}\text{C}^{12}$ absorbs an energetic neutron and emits a beta particle ( $\beta$ ). The resulting nucleus is

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Answer: (b)

Neutron absorption: ${}_{6}\text{C}^{12} + {}_{0}n^{1} \to {}_{6}\text{C}^{13}$
$\beta^-$ emission: $A$ unchanged, $Z$ up by 1: ${}_{6}\text{C}^{13} \to {}_{7}\text{N}^{13} + e^-$
So the answer is (b) ${}_{7}\text{N}^{13}$ .