The nucleus ¹¹⁵₄₈Cd, after two successive β -decay will give (a) ¹¹⁵₄₆Pa (b) ¹¹⁴₄₉In (c) ¹¹³₅₀Sn (d) ¹¹⁵₅₀Sn

Answer: (d). Each β⁻ decay keeps A the same and raises Z by 1. After two decays: A = 115, Z = 48 + 2 = 50. Z = 50 is tin, giving ¹¹⁵₅₀Sn. So the answer is (d) ¹¹⁵₅₀Sn.

The nucleus ¹¹⁵₄₈Cd, after two successive β -decay will give | NEET 1988 (AIPMT)

Q49NEET 1988 · AIPMTEasy

Radioactive Decays: Alpha, Beta, Gamma

The nucleus ${}^{115}_{48}\text{Cd}$ , after two successive $\beta$ -decay will give

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Answer: (d)

Each $\beta^-$ decay keeps $A$ the same and raises $Z$ by 1.
After two decays: $A = 115$ , $Z = 48 + 2 = 50$ .
$Z = 50$ is tin, giving ${}^{115}_{50}\text{Sn}$ .
So the answer is (d) ${}^{115}_{50}\text{Sn}$ .

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Radioactive Decays: Alpha, Beta, Gamma question from NEET 1988 (AIPMT)

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