The number of photoelectrons emitted for light of frequency v (higher than the threshold frequency (v₀) is proportional to (a) threshold frequency (v₀) (b) intensity of light (I) (c) frequency of light (v) (d) work function (φ₀)

Answer: (b). One photon ejects one electron, so number of photoelectrons ∝ number of photons falling per second. For a fixed frequency, number of photons per second ∝ intensity I. So the answer is (b) intensity of light.

The number of photoelectrons emitted for light of frequency v (higher… | MHT CET 2024 (2 May, Shift 2)

Q24MHT CET 2024 · 2 MAY · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The number of photoelectrons emitted for light of frequency $v$ (higher than the threshold frequency $(v_0)$ is proportional to

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Answer: (b)

One photon ejects one electron, so number of photoelectrons $\propto$ number of photons falling per second.
For a fixed frequency, number of photons per second $\propto$ intensity $I$ .
So the answer is (b) intensity of light.

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Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (2 May, Shift 2)

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