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MHT CET 2026 (11 Apr, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2026 (11 Apr, Shift 1)

Q23MHT CET 2026 · 11 APR · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

The number of revolutions per second made by an electron in the first Bohr orbit of hydrogen atom is (hh = Planck's constant, mm is the mass of electron and rr is the radius of the orbit.)

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Answer: (a)

  1. mvr=h2π⇒v=h2πmrmvr = \frac{h}{2\pi} \Rightarrow v = \frac{h}{2\pi m r}
  2. f=v2πr=h4π2mr2f = \frac{v}{2\pi r} = \frac{h}{4\pi^2 m r^2}
  3. So the answer is (a) h/4π2mr2h/4\pi^2 m r^2.
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