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MHT CET 2024 (11 May, Shift 2) · Mutual Inductance

Mutual Inductance question from MHT CET 2024 (11 May, Shift 2)

Q34MHT CET 2024 · 11 MAY · SHIFT 2Easy

Mutual Inductance

The number of turns in the primary of a transformer are 1000 and in secondary 3000. If 80 V a.c. is applied to the primary, the potential difference per turn of the secondary coil is

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Answer: (c)

$\dfrac{V_s}{V_p} = \dfrac{N_s}{N_p} \Rightarrow V_s = 80 \times \dfrac{3000}{1000} = 240\text{ V}$
Voltage per turn $= \dfrac{240}{3000} = 0.08\text{ V}$ (same as $80/1000$ for the primary)
So the answer is (c) 0.08 V.

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