Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Satellites - Orbital Velocity & Period›Question 39

JEE Main 2023 (8 Apr, Shift 2) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2023 (8 Apr, Shift 2)

Q39JEE Main 2023 · 8 APR · SHIFT 2Medium

Satellites - Orbital Velocity & Period

The orbital angular momentum of a satellite is L, when it is revolving in a circular orbit at height h from earth surface. If the distance of satellite from the earth centre is increased by eight times to its initial value, then the new angular momentum will be -

Show answer and solution

Answer: (d)

  1. L=mGMrL = m\sqrt{GMr}, so L∝rL \propto \sqrt{r}.
  2. Increasing the distance by eight times its value gives r′=r+8r=9rr' = r + 8r = 9r.
  3. L′=L9=3LL' = L\sqrt{9} = 3L
  4. So the answer is (d) 3L.
Report a mistake

More questions on Satellites - Orbital Velocity & Period