The output characteristics of a transistor is shown in the figure. When VCE is 10V and IC = 4.0 mA, then value of β ac is __________. Numerical answer type. Work it out, then open the answer.

Answer: 150. At VCE = 10 V, IC = 4 mA lies between the IB = 20 and 30 curves. Reading the graph: IC ≈ 3.0 mA at 20 and ≈ 4.5 mA at 30, so Δ IC ≈ 1.5 mA. βac = (Δ IC)/(Δ IB) = (1.5 mA)/(10) = 150 So βac = 150.

The output characteristics of a transistor is shown in the figure… | JEE Main 2020 (6 Sep, Shift 2)

Q80JEE Main 2020 · 6 SEP · SHIFT 2Medium

Junction Transistor

The output characteristics of a transistor is shown in the figure.

When VCE is 10V and IC = 4.0 mA, then value of $\beta$ ac is __________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 150

At $V_{CE} = 10$ V, $I_C = 4$ mA lies between the $I_B = 20\ \mu\text{A}$ and $30\ \mu\text{A}$ curves.
Reading the graph: $I_C \approx 3.0$ mA at $20\ \mu\text{A}$ and $\approx 4.5$ mA at $30\ \mu\text{A}$ , so $\Delta I_C \approx 1.5$ mA.
$\beta_{ac} = \dfrac{\Delta I_C}{\Delta I_B} = \dfrac{1.5\ \text{mA}}{10\ \mu\text{A}} = 150$
So $\beta_{ac} = 150$ .

Report a mistake

Junction Transistor question from JEE Main 2020 (6 Sep, Shift 2)

More questions on Junction Transistor