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NEET 2013 · Logic Gates

Logic Gates question from NEET 2013

Q162NEET 2013Easy

Logic Gates

The output from a NAND gate is divided into two in parallel and fed to another NAND gate. The resulting gate is a

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Answer: (a)

  1. First NAND: Y1=A⋅B‾Y_1 = \overline{A \cdot B}.
  2. Second NAND with both inputs Y1Y_1 acts as NOT: C=Y1‾C = \overline{Y_1}.
  3. C=A⋅B‾‾=A⋅BC = \overline{\overline{A \cdot B}} = A \cdot B.
  4. So the answer is (a) AND gate.
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