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JEE Main 2025 (24 Jan, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2025 (24 Jan, Shift 2)

Q54JEE Main 2025 · 24 JAN · SHIFT 2Difficult

Logic Gates

The output of the circuit is low (zero) for:

Figure

(A) X=0,Y=0X = 0, Y = 0

(B) X=0,Y=1X = 0, Y = 1

(C) X=1,Y=0X = 1, Y = 0

(D) X=1,Y=1X = 1, Y = 1

Choose the correct answer from the options given below:

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Answer: (c)

  1. The first gate is OR: output X+YX + Y.
  2. The NOR with both inputs joined acts as NOT, so output =X+Y‾= \overline{X + Y} (overall NOR).
  3. Output is 0 whenever X+Y=1X + Y = 1, i.e. for (0,1)(0,1), (1,0)(1,0) and (1,1)(1,1).
  4. So the answer is (c) (B), (C) and (D) only.
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