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JEE Main 2024 (31 Jan, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2024 (31 Jan, Shift 2)

Q73JEE Main 2024 · 31 JAN · SHIFT 2Medium

Logic Gates

Figure

The output of the given circuit diagram is -

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Answer: (d)

  1. Upper OR gets AA and Bˉ\bar{B}: A+BˉA + \bar{B}. Lower OR gets BB and Aˉ\bar{A}: Aˉ+B\bar{A} + B.
  2. Y=(A+Bˉ)+(Aˉ+B)‾Y = \overline{(A + \bar{B}) + (\bar{A} + B)}.
  3. (A+Aˉ)+(B+Bˉ)=1(A + \bar{A}) + (B + \bar{B}) = 1, so Y=1ˉ=0Y = \bar{1} = 0 for every input.
  4. So the answer is (d), output 0 in all rows.
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