P-N Junction Diode question from JEE Main 2025 (8 Apr, Shift 2)

Answer: (a)

1. The output node is pulled toward $+5$ V through the resistor; both diodes have their anodes at this node.
2. $D_2$'s cathode is at 0 V (ground), so $D_2$ is forward biased and, being ideal, clamps the node to 0 V.
3. $D_1$ then has anode at 0 V and cathode at $+5$ V, so it is reverse biased.
4. $V_{out} = 0$ V. So the answer is (a).