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NEET 2013 · Logic Gates

Logic Gates question from NEET 2013

Q163NEET 2013Medium

Logic Gates

The output (X) of the logic circuit shown in figure will be

Figure

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Answer: (a)

  1. First NAND gives A⋅B‾\overline{A \cdot B}.
  2. Second NAND has both inputs joined, so it is a NOT gate: X=A⋅B‾‾=A⋅BX = \overline{\overline{A \cdot B}} = A \cdot B.
  3. So the answer is (a) X=A⋅BX = A \cdot B.
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