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JEE Main 2026 (8 Apr, Shift 2) · Logic Gates

Logic Gates question from JEE Main 2026 (8 Apr, Shift 2)

Q17JEE Main 2026 · 8 APR · SHIFT 2Medium

Logic Gates

The output YY for the given inputs AA and BB to the circuit is:

Figure

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Answer: (b)

  1. Upper AND: A⋅BA \cdot B. Lower AND has a bubble on its A input: Aˉ⋅B\bar{A} \cdot B.
  2. Y=AB+AˉB=B(A+Aˉ)=BY = A B + \bar{A} B = B(A + \bar{A}) = B.
  3. From the waveform, B=1B = 1 for 00 to 22 s and B=0B = 0 for 22 to 33 s.
  4. So Y is 1 from 0 to 2 s and 0 from 2 to 3 s: the answer is (b).
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